[FOM] Correction to problem on order types

[Robert M. Solovay]

Joe,

	Can you elaborate what the error is? I got eleven as well. The
empty set; the one point set and then 3 times 3 where the possibilities
are open, closed, or "the long line" for each end.

	--Bob Solovay



On Sat, 5 Mar 2005 JoeShipman at aol.com wrote:

> In the statement of the problem, I should require that every open interval (a,b) with a<b is isomophic to the real numbers, not rational numbers.
>
> That was the form I had originally come up with the problem, but then I got too clever.  Dave Marker claims that changing "reals" to "rationals" allows more solutions than I had contemplated, and pointed out why my comtemplated proof for "rationals" fails.
>
> -- JS
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