LECTURE LECTURE 6
PLANE GRAPHS AND POINT LOCATION

Euler's formula relating number of vertices, edges and faces of a plana embedding of graph is a fundamental relation in computational geometry. It leads to all the favorable computational properties of planar graphs, as compared to general graphs. We introduce the notion of skeletons and their computation. In general, we need the language of cell complexes as in topology where skeletons might be called 1-complexes.

The problem of point location, Kirkpatrick's elegant solution, and the alternative of Seidel is treated.

1   Plane Graphs and Skeletons

Let G be a undirected graph G = (V,E). Let the map m assign to each v Î V a distinct point m(v) in the plane. The points are distinct in the sense that u ¹ v implies m(u) ¹ m(v). This map extends naturally to edges where e = (u,v) Î E is mapped to the open line segment m(e) = (m(u),m(v)). This extended map m is called a linear plane embedding of G if the following two conditions hold.

Not all graphs admit such a embedding; those that do are called planar graphs. We will simply say ``embedding'' instead of ``linear plane embedding''. By a plane graph we mean1 a planar graph G together with some linear plane embedding m.

Let S be a set of open line segments (called ``edges'') and points (``vertices''). We call S a skeleton if it satisfies the following properties:

Clearly, if m is an embedding of G, then the set


{m(v): v Î V}È{m(e): e Î E}
is a skeleton. Conversely, every skeleton is the embedding of a graph which we denote by G(S) = (V(S), E(S)). By abuse of language, we sometimes call S an embedding of G(S).

Given any graph G, we have the usual numerical quantities |V|, |E| and the number of connected components b(G). We will call the quantities |V|, |E| and the number of connected components of G the embedding invariants of G, and denote them by


n0(G), n1(G), b(G),
respectively. If S is a skeleton, we will write n0(S) for n0(G(S)), etc. But we can define another quantity for S, the number of regions induced by S. More precisely, consider the set K = R2 \ÈS. The set K partitions naturally into a finite number of maximally connected open sets, each of which is called a region of the embedding. Note that K has exactly one unbounded region. Let n2(S) denote the number of regions. It is less clear that n2(S) is an embedding invariant of G(S). This is however true, and will be proved below. Hence we may write n2(G) for n2(S) where S is any embedding of G. Note that n2(G) is only defined when G is planar.

Remark: Two closed line segments are said to be crossing if their relative interios intersect; otherwise they are non-crossing. Note that non-crossing line segments may share endpoints. Then a skeleton S alternatively be represented by a set of closed line segments that are non-crossing.

2   Euler's Formula for Embeddings

A skeleton S (or graph G) can be incrementally constructed via a sequence of |S| (or |V|+|E|) operations, where each operation comes under one of the following two types:

More precisely, a construction sequence for S is


S0 Í S1 Í S2 Í ¼ Í Sm
(1)
where S0 = Æ, Sm = S, and for i ³ 0, Si+1 is obtained from Si using one of our operations above. Clearly, |Si| = i for i = 0 ,¼, m.

Theorem 1 The following formula of Euler holds for any skeleton S:


n0(S) - n1(S) + n2(S) = 1 + b(S).
(2)

Proof.  We use induction on |S|. The formula is true when S is the empty set:


0 - 0 + 1 = 1 + 0.
For |S| > 0, consider any construction sequence (1) that ends in S. Let S¢ be the skeleton just before S in the sequence (so S¢ = Sm-1). By induction hypothesis, Euler's formula holds for S¢. So, we need to show that adding a vertex or an edge preserves the invariant. When we add a vertex, the only quantities in the Euler's formula (2) that change are the number of vertices and the number of connected components of the graph: both increases by 1,


n0(S) = n0(S¢)+1, b(S) = b(S¢)+1.
But these changes preserve our Euler's formula. When we add an edge, there are two possibilities: (i) the two endpoints of the edge belong to disjoint components of the graph, or (ii) they belong to a common component. In case (i), the quantities that change are


n1(S) = n1(S¢)+1, b(S) = b(S¢)-1.
Thus, we gained an edge but lost one connected component. This preserves the Euler's formula (2). In case (ii), the changes are


n1(S) = n1(S¢)+1, n2(S) = n2(S¢)+1.
Thus, we gained an edge as well an a region (one of the original regions split into two). Again, Euler's formula continues to hold. Q.E.D.

The above proof apparently depends on a choice of a sequence (1), namely, on the order in which vertices and edges are introduced. But the numerical quantity n2(S) depends only on the final set S, and not on the sequence of operations to reach S. We now show that n2(S) depends only on the graph G(S).

Corollary 2 The number n2(G) is well-defined for a planar graph G.

Proof.  Let S be any embedding of G. We know that n0(S), n1(S), b(S) are functions of G alone, independent of the choice of S. Thus Euler's formula (2) for S implies that n2(S) is also a function of G alone. Q.E.D.

Remark: We can equally develop this section by defining the ``dual'' of a construction sequence: We may define a destruction sequence for any embedding S to be a sequence (S0, S1 ,¼, Sm) where S0 = S, and each Si+1 is obtained from Si by removing an arbitrary edge or by removing a vertex that is no longer incident on any edge.

3   Consequences of Euler's Formula

Let G = (V,E) be a planar graph. Our first goal is to bound the average degree d = d(G) of vertices in a planar graph:


d = 1
n0

å
v Î V 
d(v)
where d(v) is the degree of v, i.e., number of edges in E incident on v. Now åv Î Vd(v) can be regarded as counting the number of (vertex, edge) incidences from the viewpoint of the vertices. We can count also these incidences from the view point of the edges, and this number is 2 n1 since each edge is involved in two such incidences. It follows that


d = 2n1
n0
.
(3)
In combinatorics, whenever we can count a quantity in two independent ways, we have a non-trivial relation such as (3). Good, let us do this again. Why not count the number of (edge, region) incidences. The difference is that we now only get bounds (upper or lower) on the desired quantity. From the viewpoint of the edges, this count is exactly 2n1. Actually, we have a technicality here: sometimes, an edge may have the same region on both of its sides - do we count this as one or two incidences? If we count this as one (edge, region) incidence, then 2n1 is not exact, but an upper bound. But it turns out not to matter. From the viewpoint of the regions, we get a lower bound of 3n2 on the number of incidences. This lower bound is the first time we actually exploit the fact that our embedded edges are linear curves, so that each region is bounded at least three edges. Thus we have


2n1 ³ 3n2.
(4)
Thus the number of regions n2 is at most 2n1/3. Plugging this inequality into Euler's formula to eliminate n2, we obtain


n0 - n1 + 2n1
3
³
1 +b
n0
³
1 + n1
3
.
Thus the average degree is less than 6:


2n1
n0
< 2n1
n1/3
= 6.
But at most half of the vertices has twice the average degree or more. Thus we have shown:

In a plane graph G with n nodes, at least ë n/2 û = ë n0(G)/2 û of its vertices has degree less than 12.

Let us summarize: In a plane graph with v vertices and e edges and r regions,


r £ 2e/3,        e £ 3v.
Thus r £ 2v. Morever, at least ë v/2 û of the vertices have degree at most 11.

4   Data Structures for Subdivisions

The information represented by an embedding (or a skeleton) needs to be rationally encoded to support algorithms for such embeddings. Several data structures have been proposed in the literature, and we now examine some of them.

The Problem with Holes.   First some terminology: if f,f¢ are two adjacent faces, with f¢ contained in the closure of f, then we say that f¢ bounds f. The dimension of f¢ will be less than the dimension of f. The boundary of a region will in general be comprised of several boundary components, which are pairwise disjoint simple polygons (=vertices and edges), For bounded regions, there is a distinguished boundary component, namely, the the outermost boundary. The non-distinguished boundary components can be seen to bound holes. Connected regions that do not have holes are said to be simply-connected. Alternatively, for a non-empty skeleton, a region is simply connected iff it is bounded and has one boundary component.

One way to convert bounded regions into simply-connected regions is to introduce an edge to connect the boundary to each hold to the rest of the boundary. Such an edge (called an isthmus) is characterized by having the same region on both sides of the edge. For simplicity, we often assume that the bounded regions are simply-connected.

Requirements.   Let S be a skeleton. What do we require from a data structures D(S) for P(S)? Basically, we expect to search from any face of P(S) its adjacent faces quickly.

Let us give an example of an operation that does not automatically fall out of such representations: given a vertex, what is the edge (if any) that is vertically above it? This query cannot be obtained in constant time using the above information.

First Attempt: Augmented Adjacency Lists.   To indicate that the correct data structure is not entirely trivial, let us explore the reasonable suggestion to represent P(S) by any efficient representation of the graph G(S), augmented by additional information that arises from the embedding. One of the most useful representations of graphs is the adjacency list representation: we have a vertex list and an edge list; for each edge in the edge list, we store its pair of endpoints, and for each vertex v in the vertex list, we store an adjacency list A(v) comprising the edges that are bounded by v. We now propose to represent subdivisions by augmenting the adjacency list representation. The following additional information may be provided.

Unfortunately, this data structure does not meet one of our above requirements. How do we traverse around the boundary of a region efficiently? The adjacency does encode information to support this traversal, but not in a form that is easily accessible. In particular, we cannot get from one bounding edge e to the ``next edge'' e¢ in constant time. It takes time proportional to the degree of the vertex that is incident to both e and e¢. Nevertheless, this simple ``augmented adjacency list'' structure may be useful if going around the boundary of a region is not important.

An alternative solution would be to further augment our augmented adjacency list structure: store with each face, a list of all the edges bounding the face. But this is duplicating information, which is sometimes undesirable.

The DCEL Structure.   There is no simple way to modify the augmented adjacency list representation above. Instead we must take it apart: the problem lies in the the monolithic ``adjacency lists'' (inherited from graphs). We will take the information in these lists and distribute this information among the edges. Each edge is now given an arbitrary direction. This amounts to specifying one incident vertex of e as the start and the other as the stop vertex. Relative to this direction, we have two faces called the left and right faces of e. We define the left and right successors of of e to be the two edges that are incident on the e.stop and which bound the left and right (respectively) faces of e. Similarly, we can define the left and right predecessors of e; these are edges incident on e.start and bounding the left and right (respectively) faces of e. See figure 1(a).


Picture Omitted

Picture Omitted
Figure 1: Successor and predecessor edges

.

Half-Edge Data Structure.   The DCEL Structure has one unsatisfactory feature, its arbitrary assignment of direction to edges. We can remove this arbitrariness by splitting each edge into two half-edges. The result data structure is the so-called half-edge data structure. So the two half-edges are really the same edge with opposite orientations. Such a pair is called a twin. For each half-edge h, let h.twin be its twin. Thus, h.twin.twin = h. The end points of h are h.start and h.stop and we consider h to be directed from h.start to h.stop. Thus h.twin.start = h.stop and h.twin.stop = h.start. We view each half-edge as bounding a single face, denoted h.face. This is the face that lies on the right side of the directed half-edge. We also have h.succ, h.pred refering to the half-edges that bound h.face and incident on h.stop and h.start (respectively).

This data structure will be our default data structure for plane subdivisions (and any general surface mesh). For this reason, let us be explicit about our conventions for this data structure.

In applications, parts of this data structure may be omitted. For instance, if it is sufficient to traverse the boundary of a face in only one direction, then we can drop the predecessor links for each half-edge. Often, we may omit the list of faces and associated pointers.

What is the complexity of this representation? When it is O(n0(S)+n1(S)+n2(S)) = O(n) where n = n0(S) is usually taken to be the size of this subdivision.

Variations.   Some variants are called ``winged edges data structures'', where the ``wing'' terminology is suggested by the directions drawn on edges. Sometimes, redundant information may be provided to provide constant speedup. In some applications, some of the links can be omitted. As noted above, we may often drop all information related to the regions. If this is done, we may achieve significant improvement in performance (constant factor, of course). Another remark is that our skeletons allow ``dangling edges'' or handles which do not appear essential. But one reason to allow them is that some incremental algorithms, our data structre may pass through intermediate stages with such handles which will eventually be removed.

Quad-Edges Data Structure and Duality.   The quad-edge data structure was introduced by Guibas and Stolfi. Let us now restrict attention to regions that are simply connected. Then there is a dual graph D(G) in which the regions of G are vertices of D(G), and the edges of D(G) are still the edges of D(G). In general, D(G) may no longer be a simple graph - it may have multiple (or parallel) edges. See figure 2.


Picture Omitted

Picture Omitted
Figure 2: Dual Graphs.

The quad-edge data structure for a skeleton S has the elegant symmetry between vertices and regions, thus giving no preferences to the graph G(S) or its dual D(G(S)).

Remarks. For an in-depth discussion on designing a data structure for surfaces in a general geometric library, we refer to Kettner [1].

5   Triangulation of a Subdivision

A connected subset X Í R2 is y-monotone if every horizontal line H(t) intersects X in a connected set H(t)ÇX. Note that if H(t)ÇX is empty, it is considered a connected set. Let P be a subdivision of the plane. We say P is y-monotone if every bounded face of P is y-monotone. We say P is triangulated if bounded region is triangulated. Note that

6   Point Location and Kirkpatrick's Structure

Let S be a skeleton. It induces a partition P(S) of R2 into disjoint sets which comprise the vertices and edges in S, as well as the regions as defined before. Thus S Í P and the set of regions is P\S. Call P = P(S) the called the planar subdivision induced by S. Each f Î P is called a face of the subdivision. Thus the faces are vertices (or 0-faces), edges (or 1-faces) or regions (or 2-faces).

Now assume that the underlying graph G(S) is connected, i.e., b(G(S)) = 1). The planar point location problem for S asks us to construct a data structure D(S) such that for any point q Î R2, we can use D(S) to efficiently determine the face f(q) of the subdivision P(S) that contains q. Here q is called the query point.

We now describe a beautiful datastructure D(S) of Kirkpatrick to solve the planar point location problem. We assume that the subdivision P(S) is triangulated (that is, each region, except for the infinite region, is a triangle). A subset U Í V(S) is called an independent set if no two vertices in U are connected by an edge. Kirkpatrick defines a sequence


S0, S1 ,¼, Sh
of embeddings where S0 is the original S, and Si+1 is obtained from Si be removing an independent subset Ui Í Vi(S). Thus


V(Si+1) = V(Si) \Ui.
We now describe E(Si+1). This is obtained from E(Si) be removing any edge that is incident on a removed vertex of Ui, and by re-introducing edges to re-triangulate the regions that are no longer triangulated.

It is instructive to understand this re-triangulation process. Say u is a removed vertex, and as a result, we have to remove k edges that are incident on u. This create a ``star-shaped region'' that is centered at u with k bounding segments. To re-triangulate this region, we only need to k-3 new edges. Note that because we assume U is an independent set, the star-shaped region for the points in U are pairwise disjoint. Hence the re-triangulation for each u can proceed independently.

This completes the description of Si+1. Intuitively, Si+1 is a ``simplified version'' of Si. We step this simplification process when |Si| is less than some constant. We may represent each P(Si) using some standard topological representation of subdivisions (e.g., half-edge data structure).

There is another important set of links in our hierarchical data structure: each face f Î P(Si+1) points to its ``cause'' in P(Si): if f occurs as f¢ Î P(Si), then f¢ is the ``direct cause'' of f. If not, f points to the vertex u in P(Si) whose removal led to the creation of f (in this case, f is an edge or a region). Here, u the ``indirect cause'' of f. We have now completely describe D(S), except for one addition detail - how is the independent sets Ui specified?

Let us see how we can use D(S) for point location: given a query point q, we locate the face f of P(Sh) that contains q. In general, when we have found the face fi+1 in P(Si+1) that contains q, we can find the face the face fi in P(Si) that contains q as follows: follow ``cause link'' of fi+1 to some f¢ in P(Si). If f¢ is a direct cause then fi is simply f¢. Otherwise, we need to search the edges and regions in P(Si) that are incident on f¢ to find fi. How much time does this search take? This depends on the degree of f¢. We would like this degree to be bounded.

Complexity of Kirkpatrick's Solution.   This brings us to the final detail: Kirkpatrick shows that we can choose Ui so that

Can we find Ui with properties (a) and (b)? This is actually a simple consequence of our bound that about half of the vertices has degree at most 11. We just pick vertices of degree at most 11 in any order, making sure that no two picked vertices are adjacent. So, each picked vertex cause us to eliminate at most 12 vertices from further consideration. Thus, we can continue this picking for at least n/24 times since at least n/2 of the nodes must be eliminated before this process halts.

Let us deduce the computational significance of (a) and (b). From (b), it follows that the hierarchy () is O(log|V(S)|) = O(lgn). In fact, it is at most


h £ log12/11 |V(S)|.
(5)
From the bound n1(S) < 3n0(S) in the previous section, we are justified to define the size of S to be n = n0(S). From (a) we see that we can do point location for q in Si in constant time, given that we have the answer to the query in Si+1. Combined with (5), we conclude that Kirkpatrick's structure can answer queries in O(logn) time.

Discussion.   Unfortunately, this beautiful data structure does not appear to be useful in practice. There are two reasons. One is that the hidden constant in the logn time performance seems to be too large. Let the time be Clgn. Note that C depends linearly 1/lg(24/23) + 11. We will next examine more practical alternatives. The second is that the approach requires the subdivision be a triangulation. We will show how to get around this problem.

Kirkpatrick's result motivates the question: what other numbers can be used in place of the constants (d, f) = (11, 24) in the above proof? It turns out that we can use (d, f) = (9, 35/2).

7   REMARKS

Dynamic Maps.   See Teillaud [].

Consistency Problem.   Given a half-edge data structure, how can we verify that it is consistent? In practice, this is an important issue, since algorithms often construct erroneous structures because of numerical roundoff errors.

Exercises

Exercise 6.1:

Suppose G(S) is a connected graph and we want a construction sequence (S0 ,¼, Sm) for S with the property that each G(Si) is connected. In this case, we replace the operation of adding an isolated vertex by an operation that simultaneously adds an isolated vertex and an edge that connects it to the rest of the graph. Write a constructive geometry package supporting this set of operations. ¨

Exercise 6.2:

Give a detail accounting of the space needs for our half-edge data structure. Compare this to the quad-edge and the DCEL data structures. ¨

  (End of Exercise)

References

[1]
L. Kettner. Using generic programming for designing a data structure for polyhedral surfaces. Computational Geometry: Theory and Applications, 13:65-90, 1999.


Footnotes:

1 This technical distinction between ``planar graph'' and ``plane graph'' is possibly confusing in ordinary speech.


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