The original input was: 3  0 1 5 1  0 1 5 1  3 1 5 1 
The (sorted) input is:  3  0 1 5 1  0 1 5 1  3 1 5 1 

This detailed printout gives the state and remaining burst for each process

Before cycle    0:   unstarted  0  unstarted  0  unstarted  0.
Before cycle    1:     running  1      ready  0  unstarted  0.
Before cycle    2:     blocked  1      ready  0  unstarted  0.
Before cycle    3:     running  1      ready  0  unstarted  0.
Before cycle    4:     blocked  1      ready  0      ready  0.
Before cycle    5:     running  1      ready  0      ready  0.
Before cycle    6:     blocked  1      ready  0      ready  0.
Before cycle    7:     running  1      ready  0      ready  0.
Before cycle    8:     blocked  1      ready  0      ready  0.
Before cycle    9:     running  1      ready  0      ready  0.
Before cycle   10:  terminated  0    running  1      ready  0.
Before cycle   11:  terminated  0    blocked  1      ready  0.
Before cycle   12:  terminated  0    running  1      ready  0.
Before cycle   13:  terminated  0    blocked  1      ready  0.
Before cycle   14:  terminated  0    running  1      ready  0.
Before cycle   15:  terminated  0    blocked  1      ready  0.
Before cycle   16:  terminated  0    running  1      ready  0.
Before cycle   17:  terminated  0    blocked  1      ready  0.
Before cycle   18:  terminated  0    running  1      ready  0.
Before cycle   19:  terminated  0 terminated  0    running  1.
Before cycle   20:  terminated  0 terminated  0    blocked  1.
Before cycle   21:  terminated  0 terminated  0    running  1.
Before cycle   22:  terminated  0 terminated  0    blocked  1.
Before cycle   23:  terminated  0 terminated  0    running  1.
Before cycle   24:  terminated  0 terminated  0    blocked  1.
Before cycle   25:  terminated  0 terminated  0    running  1.
Before cycle   26:  terminated  0 terminated  0    blocked  1.
Before cycle   27:  terminated  0 terminated  0    running  1.
The scheduling algorithm used was Uniprocessor

Process 0:
	(A,B,C,IO) = (0,1,5,1)
	Finishing time: 9
	Turnaround time: 9
	I/O time: 4
	Waiting time: 0

Process 1:
	(A,B,C,IO) = (0,1,5,1)
	Finishing time: 18
	Turnaround time: 18
	I/O time: 4
	Waiting time: 9

Process 2:
	(A,B,C,IO) = (3,1,5,1)
	Finishing time: 27
	Turnaround time: 24
	I/O time: 4
	Waiting time: 15

Summary Data:
	Finishing time: 27
	CPU Utilization: 0.555556
	I/O Utilization: 0.444444
	Throughput: 11.111111 processes per hundred cycles
	Average turnaround time: 17.000000
	Average waiting time: 8.000000