Write a (threads) library that acts as a mini-scheduler and implements thread_create, thread_exit, thread_wait, thread_yield, etc. The central data structure maintained and used by this library is the thread table, the analogue of the process table in the operating system itself.
Advantages
Disadvantages
Move the thread operations into the operating system itself. This naturally requires that the operating system itself be (significantly) modified and is thus not a trivial undertaking.
One can write a (user-level) thread library even if the kernel also has threads. This is sometimes called the M:N model since M user mode threads run on each of N kernel threads. Then each kernel thread can switch between user level threads. Thus switching between user-level threads within one kernel thread is very fast (no context switch) and we maintain the advantage that a blocking system call or page fault does not block the entire multi-threaded application since threads in other processes of this application are still runnable.
Skipped
The idea is to automatically issue a create thread system call upon message arrival. (The alternative is to have a thread or process blocked on a receive system call.) If implemented well the latency between message arrival and thread execution can be very small since the new thread does not have state to restore.
Definitely NOT for the faint of heart.
A race condition occurs when two (or more) processes are about to perform some action. Depending on the exact timing, one or other goes first. If one of the processes goes first, everything works, but if another one goes first, an error, possibly fatal, occurs.
Imagine two processes both accessing x, which is initially 10.
We must prevent interleaving sections of code that need to be atomic with respect to each other. That is, the conflicting sections need mutual exclusion. If process A is executing its critical section, it excludes process B from executing its critical section. Conversely if process B is executing is critical section, it excludes process A from executing its critical section.
Requirements for a critical section implementation.
The operating system can choose not to preempt itself. That is, we do not preempt system processes (if the OS is client server) or processes running in system mode (if the OS is self service). Forbidding preemption for system processes would prevent the problem above where x<--x+1 not being atomic crashed the printer spooler if the spooler is part of the OS.
But simply forbidding preemption while in system mode is not sufficient.
Initially P1wants=P2wants=false Code for P1 Code for P2 Loop forever { Loop forever { P1wants <-- true ENTRY P2wants <-- true while (P2wants) {} ENTRY while (P1wants) {} critical-section critical-section P1wants <-- false EXIT P2wants <-- false non-critical-section } non-critical-section }
Explain why this works.
But it is wrong! Why?
Let's try again. The trouble was that setting want before the loop permitted us to get stuck. We had them in the wrong order!
Initially P1wants=P2wants=false Code for P1 Code for P2 Loop forever { Loop forever { while (P2wants) {} ENTRY while (P1wants) {} P1wants <-- true ENTRY P2wants <-- true critical-section critical-section P1wants <-- false EXIT P2wants <-- false non-critical-section } non-critical-section }
Explain why this works.
But it is wrong again! Why?
So let's be polite and really take turns. None of this wanting stuff.
Initially turn=1 Code for P1 Code for P2 Loop forever { Loop forever { while (turn = 2) {} while (turn = 1) {} critical-section critical-section turn <-- 2 turn <-- 1 non-critical-section } non-critical-section }
This one forces alternation, so is not general enough. Specifically, it does not satisfy condition three, which requires that no process in its non-critical section can stop another process from entering its critical section. With alternation, if one process is in its non-critical section (NCS) then the other can enter the CS once but not again.
The first example violated rule 4 (the whole system blocked). The second example violated rule 1 (both in the critical section. The third example violated rule 3 (one process in the NCS stopped another from entering its CS).
In fact, it took years (way back when) to find a correct solution. Many earlier “solutions” were found and several were published, but all were wrong. The first correct solution was found by a mathematician named Dekker, who combined the ideas of turn and wants. The basic idea is that you take turns when there is contention, but when there is no contention, the requesting process can enter. It is very clever, but I am skipping it (I cover it when I teach distributed operating systems in V22.0480 or G22.2251). Subsequently, algorithms with better fairness properties were found (e.g., no task has to wait for another task to enter the CS twice).
What follows is Peterson's solution, which also combines turn and wants to force alternation only when there is contention. When Peterson's solution was published, it was a surprise to see such a simple soluntion. In fact Peterson gave a solution for any number of processes. A proof that the algorithm satisfies our properties (including a strong fairness condition) for any number of processes can be found in Operating Systems Review Jan 1990, pp. 18-22.
Initially P1wants=P2wants=false and turn=1 Code for P1 Code for P2 Loop forever { Loop forever { P1wants <-- true P2wants <-- true turn <-- 2 turn <-- 1 while (P2wants and turn=2) {} while (P1wants and turn=1) {} critical-section critical-section P1wants <-- false P2wants <-- false non-critical-section non-critical-section
The word atomically means that the two actions performed by TAS(x) (testing, i.e., returning the old value of x and setting , i.e., assigning true to x) are inseparable. Specifically it is not possible for two concurrent TAS(x) operations to both return false (unless there is also another concurrent statement that sets x to false).
With TAS available implementing a critical section for any number of processes is trivial.
loop forever { while (TAS(s)) {} ENTRY CS s<--false EXIT NCS
Remark: Tanenbaum does both busy waiting (as above) and blocking (process switching) solutions. We will only do busy waiting, which is easier. Sleep and Wakeup are the simplest blocking primitives. Sleep voluntarily blocks the process and wakeup unblocks a sleeping process. We will not cover these.
Homework: Explain the difference between busy waiting and blocking.
Remark: Tannenbaum use the term semaphore only for blocking solutions. I will use the term for our busy waiting solutions. Others call our solutions spin locks.
The entry code is often called P and the exit code V. Thus the critical section problem is to write P and V so that
loop forever P critical-section V non-critical-sectionsatisfies
Note that I use indenting carefully and hence do not need (and sometimes omit) the braces {} used in languages like C or java.
A binary semaphore abstracts the TAS solution we gave for the critical section problem.
while (S=closed) {} S<--closed <== This is NOT the body of the whilewhere finding S=open and setting S<--closed is atomic
The above code is not real, i.e., it is not an implementation of P. It is, instead, a definition of the effect P is to have.
To repeat: for any number of processes, the critical section problem can be solved by
loop forever P(S) CS V(S) NCS
The only specific solution we have seen for an arbitrary number of processes is the one just above with P(S) implemented via test and set.
Remark: Peterson's solution requires each process to know its processor number. The TAS soluton does not. Moreover the definition of P and V does not permit use of the processor number. Thus, strictly speaking Peterson did not provide an implementation of P and V. He did solve the critical section problem.
To solve other coordination problems we want to extend binary semaphores.
Both of the shortcomings can be overcome by not restricting ourselves to a binary variable, but instead define a generalized or counting semaphore.
while (S=0) {} S--where finding S>0 and decrementing S is atomic
These counting semaphores can solve what I call the semi-critical-section problem, where you premit up to k processes in the section. When k=1 we have the original critical-section problem.
initially S=k loop forever P(S) SCS <== semi-critical-section V(S) NCS
Initially e=k, f=0 (counting semaphore); b=open (binary semaphore) Producer Consumer loop forever loop forever produce-item P(f) P(e) P(b); take item from buf; V(b) P(b); add item to buf; V(b) V(e) V(f) consume-item
Lab #2 will be officially assigned next tuesday. It will involve simulating scheduling policies. I hope to have it written before then and, if I do, it will be posted on the web page and email will be sent to the mailing list.
Busy wait | block/switch | |
---|---|---|
critical | (binary) semaphore | (binary) semaphore |
semi-critical | counting semaphore | counting semaphore |
Busy wait | block/switch | |
---|---|---|
critical | enter/leave region | mutex |
semi-critical | no name | semaphore |
A classical problem from Dijkstra
The purpose of mentioning the Dining Philosophers problem without giving the solution is to give a feel of what coordination problems are like. The book gives others as well. We are skipping these (again this material would be covered in a sequel course). If you are interested look, for example, here.
Homework: 31 and 32 (these have short answers but are not easy). Note that the problem refers to fig. 2-20, which is incorrect. It should be fig 2-33.