Axiom of Choice/(ultra)filters
pax0 at seznam.cz
pax0 at seznam.cz
Sat Mar 19 17:01:02 EDT 2022
Dear FOMers,
many years ago I asked here a question (copied below) about selectors on all
(ultra)filters.
I got this answer:
>(1) as strong as ZFC, but (2) weaker.
When I went through the proof recently, I realized that in (1) there is a
kind of unwanted triviality exploited in the proof
(obtaining AC from (1)). So I would now modify it to
(1 ") ZF+{on every NON-PRINCIPAL filter, there is a selector}
Does this modified (1 ") still imply full (AC) ?
What is its relationship with (2) ?
---End of my question---
Thank you, Jan Pax
"I have a question regarding the Axiom of Choice,
what is the strength of the following two theories:
(1) ZF+{on every filter, there is a selector},
(2) ZF+{on every ultrafilter, there is a selector} .
More precisely, are they strictly weaker then ZFC?
Here, by a selector on a set X I mean a function with the domain all
nonempty sets in X and
with f(x) \in x for every member x in its domain.
Then ZFC is equivalent to ZF+{on every set, there is a selector}.
Thank you
"
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