Strict formalism
Timothy Y. Chow
tchow at math.princeton.edu
Mon Dec 14 09:57:12 EST 2020
In my Mathematical Intelligencer article on the consistency of arithmetic,
I introduced the term "strict formalism." Recently, I came up with a way
to present my point about strict formalism in a particularly vivid manner.
Suppose someone says they're a formalist and suggests that the consistency
of PA is an open problem. Here is my reply.
Consider the following "formal system" which I will call Z. Z has just
one axiom: "0" (i.e., a string of length one, comprising a single numeral,
0). It also has just one rule of inference:
if "x" is a theorem then so is "x0"
So for example, "00" is a theorem, "000" is a theorem, and so on. Now I
present the following conjecture.
Conjecture. "1" is not a theorem.
In other words, the string of length one, comprising a single numeral, 1,
cannot be obtained from the axiom of Z by any finite number of
applications of the rule of inference.
The above Conjecture might seem ridiculous. However, I claim that for the
strict formalist, not only is the Conjecture non-trivial---it remains an
open problem. A strict formalist can play the Z game and can verify, on a
case-by-case basis, that "00" is a theorem and "000" is a theorem, and so
forth. However, to conclude that "1" is not a theorem requires
*mathematical reasoning about abstract objects* which a strict formalist
is not entitled to.
If a formalist claims to *know* that the above Conjecture is true, then
the burden of proof is on the formalist to articulate precisely, and
defend, the principles---which of necessity must go beyond the principles
of strict formalism---according to which he or she is able to arrive at
that conclusion.
Tim
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