[FOM] Eliminating AC

[Robert Solovay]

L and V have the same integers. But AC holds in L. So a proof of an
arithmetical result in ZFC implies it holds in L, hence in V.

-- Bob Solovay

On Wed, Mar 20, 2013 at 5:52 PM, Joe Shipman <JoeShipman at aol.com> wrote:
> What is the simplest way to see that any arithmetical consequence of ZFC is a consequence of ZF?
>
> -- JS
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