[FOM] Algebraic closure of Q/difficulties
Harvey Friedman
friedman at math.ohio-state.edu
Sun May 14 14:26:20 EDT 2006
On 5/14/06 3:17 AM, "Robert M. Solovay" <solovay at Math.Berkeley.EDU> wrote:
> Harvey,
>
> Of course, none of this shows that the result you are trying to
> prove isn't true. Indeed, perhaps there is a correct proof along the rough
> lines of your current attempt.
>
Of course, as usual, you are quite right. There are several holes in my
"argument".
I look forward to somebody filling them in.
To reacap Chow's question:
PROBLEM: Is the uniqueness of algebraic closures of Q equivalent to some
simple form of the axiom of choice, over ZF?
CANDIDATE: A countable union of finite sets is countable.
This easily implies uniqueness of algebraic closures of Q, since every
algebraic closure of Q is a countable union of finite sets.
Harvey Friedman
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