FOM: No Weakest Axiom of Infinity

Neil Tennant neilt at
Fri Jul 7 08:45:56 EDT 2000

Allen Hazen's closing question could be extended to:

Is there a uniform way of generating an infinite sequence S of ever-weaker
*but natural* axioms of infinity, such that for any axiom of infinity
(not necessarily in S) there will be a weaker member of S?

Neil W. Tennant
Professor of Philosophy and Adjunct Professor of Cognitive Science
230 North Oval
The Ohio State University

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